x=(4x^2+6x+7)

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Solution for x=(4x^2+6x+7) equation: 



x=(4x^2+6x+7)

We move all terms to the left:

x-((4x^2+6x+7))=0



We calculate terms in parentheses: -((4x^2+6x+7)), so:

(4x^2+6x+7)

We get rid of parentheses

4x^2+6x+7

Back to the equation:

-(4x^2+6x+7)



We get rid of parentheses

-4x^2+x-6x-7=0

We add all the numbers together, and all the variables

-4x^2-5x-7=0

a = -4; b = -5; c = -7;
Δ = b2-4ac
Δ = -52-4·(-4)·(-7)
Δ = -87
Delta is less than zero, so there is no solution for the equation

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